Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 60: 60a

Answer

$\vec{a} =9\hat{i}+12\hat{j}$

Work Step by Step

Given vectors: $\vec{a}-\vec{b}=2\vec{c}$ $\vec{a}+\vec{b}=4\vec{c}$ $\vec{c}=3\hat{i}+4\hat{j}$ Now substitute $\vec {c}$ value in above two equations: $\vec{a}-\vec{b}=2(3\hat{i}+4\hat{j}) $ $\vec{a}-\vec{b}=6\hat{i}+8\hat{j}..............equation\ (1)$ and $\vec{a}+\vec{b}=4(3\hat{i}+4\hat{j})$ $\vec{a}+\vec{b}=12\hat{i}+16\hat{j}................equation (2)$ Add equation (1) and equation (2); $\vec{a}-\vec{b}+\vec{a}+\vec{b} =6\hat{i}+8\hat{j}+12\hat{i}+16\hat{j} $ $2\vec{a} =18\hat{i}+24\hat{j}$ $\vec{a} =9\hat{i}+12\hat{j}$
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