Answer
$d\approx6.42m$
Work Step by Step
We use the distance formula and the given values to solve:
$d=\sqrt {x^{2}+y^{2}+z^{2}}=\sqrt {(3.00m)^{2}+(3.70m)^{2}+(4.30m)^{2}}\approx6.42m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 3 - Vectors - Problems - Page 60: 64a
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