Answer
$x=90m$
Work Step by Step
We know the following equation:
$v_{f}^{2}=v_{0}^{2}+2ax$
$=\frac{v_{f}^{2}-v_{0}^{2}}{2a}$
We plug in the known values to obtain:
$x=\frac{(30m/s)^{2}-(0m/s)^{2}}{2(5m/s^{2})}=90m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 37: 80d
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