Answer
The building is $82.3m$ tall.
Work Step by Step
We know the following equation:
$y=v_{0}t+\frac{1}{2}gt^{2}$
We plug in the known values to obtain:
$y=(15.68m/s)(6.00s)+\frac{1}{2}(-9.8m/s^{2})(6.00s)^{2}$
$y\approx-82.3m$
The building is $82.3m$ tall.
