Answer
$h\approx12.5m$
Work Step by Step
We know the following equation:
$h=v_{0}t+\frac{1}{2}gt^{2}$
We plug in the known values to obtain:
$h=(15.68m/s)(1.60s)+\frac{1}{2}(-9.8m/s^{2})(1.60s)^{2}$
$h\approx12.5m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 37: 72b
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