Answer
$K = 4.9\times 10^7~J$
Work Step by Step
We can find the rotational kinetic energy:
$K = \frac{1}{2}I\omega^2$
$K = (\frac{1}{2})(\frac{1}{2}MR^2)(\omega)^2$
$K = (\frac{1}{4})(MR^2)(\omega)^2$
$K = (\frac{1}{4})(500~kg)(1.0~m)^2(200\pi~rad/s)^2$
$K = 4.9\times 10^7~J$
