Answer
The tangential acceleration of a point on the rim is $~~0.402~m/s^2$
Work Step by Step
We can find the tangential acceleration of a point on the rim:
$a_t = \alpha~r$
$a_t = (14.2~rad/s^2)(0.0283~m)$
$a_t = 0.402~m/s^2$
The tangential acceleration of a point on the rim is $~~0.402~m/s^2$
