Answer
Equation 10-12 implies that the angular acceleration $\alpha$ should be the slope of the $\omega$ vs $t$ graph. Thus, $$\alpha=9 / 6=1.5 \mathrm{rad} / \mathrm{s}^{2}$$
Work Step by Step
Equation 10-12 implies that the angular acceleration $\alpha$ should be the slope of the $\omega$ vs $t$ graph. Thus, $$\alpha=9 / 6=1.5 \mathrm{rad} / \mathrm{s}^{2}$$
