Answer
$v_d=10.9i+26.7j \frac{m}{s}$
Work Step by Step
We know that the total energy is conserved
$\implies m_nv_n+m_dv_d=m_tv_t$
This can be rearranged as:
$v_d=\frac{m_tv_t-m_nv_n}{m_d}$
We plug in the known values to obtain:
$v_d=\frac{3.02(15.1i+22.6j)-1.01(23.5i+14.4j)}{2.010}$
$v_d=10.9i+26.7j \frac{m}{s}$
