Answer
$\vec{v_2}= -10.6i-2.8j$
Work Step by Step
We know that the sum of the momentums will be 0, so:
$0 = 12(53.0i+14.0j)+ \vec{v_2}m_2$
$\vec{v_2}=-\frac{12}{60}(53.0i+14.0j)$
$\vec{v_2}= -10.6i-2.8j$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 9 - Exercises and Problems - Page 163: 20
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