Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems - Page 163: 29

Answer

We see that half of the kinetic energy was lost as a result of the collision.

Work Step by Step

We find the velocity of each of the masses after the collision, calling v the velocity of the moving mass before the collision: $v_f = \frac{mv}{m+m}=.5v$ We compare the kinetic energies: $k_0=\frac{1}{2}mv^2$ $k_f= \frac{1}{2}(2m)(.5v)^2 = \frac{1}{4}mv^2$ Thus, we see that half of the kinetic energy was lost as a result of the collision.
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