Answer
Please see the work below.
Work Step by Step
(a) We know that
$F=ma$
We plug in the known values to obtain:
$F=220\times 10^{-9}\times 980$
$F=2.156\times 10^{-4}N$
(b) We can find the impulse as
$I=F\Delta t$
We plug in the known values to obtain:
$I=(2.156\times 10^{-7})(1.2\times 10^{-3})$
$I=2.6\times 10^{-7}Ns$
(c) We know that change in momentum=Impulse
$\implies \Delta P=2.6\times 10^{-7}\frac{Kg\space m}{s}$
