Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 300: 56

Answer

$61^{\circ}C$

Work Step by Step

Each of them have the same specific heat, so we can simply average the temperatures using the masses in grams: $T = \frac{(90)(168)+(3)(84)}{168+84}=61^{\circ}C$
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