Answer
Please see the work below.
Work Step by Step
We know that
$(\frac{1}{2})Mv^2=4mc\Delta T$
This can be rearranged as:
$\Delta T=\frac{mv^2}{8mc}$
We plug in the known values to obtain:
$\Delta T=\frac{(1500)(\frac{40}{3.6})^2}{(8)(5.0)(502)}$
$\Delta T=9.2C^{\circ}$
