Answer
Please see the work below.
Work Step by Step
We know that
$Q=mc\Delta T$
We plug in the known values to obtain:
$Q=(0.330)(4184)(100-10)$
$Q=124300J$
Now we can find the time as
$t=\frac{Q}{P}$
$t=\frac{124300}{900}$
$t=140s = 2.3 min$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 16 - Exercises and Problems - Page 300: 49
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