Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 300: 42

Answer

$55.2 \ kPa$

Work Step by Step

We know the following equation: $\frac{P_2}{P_1}=\frac{T_2}{T_1}$ Thus, we find: $\frac{274.16}{273.16}=\frac{P_2}{55} \\ P_2 = 55.2 \ kPa$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.