College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 28

Answer

$0.2425m^{3}$

Work Step by Step

Using ideal gas law for fixed number of moles, $\frac{PV}{T}=constant$ T1=92F=306.48K; P1=20 units T2=32F=273.15K; P2=14.7 units Therefore, $\frac{P1\times V1}{T1}=\frac{P2\times V2}{T2}$ Or, $\frac{20\times0.2}{306.48}=\frac{14.7\times V}{273.15}$ $V=0.2425m^{3}$
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