Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 13

a). $0.555$ b). $11$%

a). $F=1.8C+32$ $C=\frac{F-32}{1.8}$ However, at high temperatures, $F-32=F$ So, $C=\frac{F}{1.8}=0.555F$ Hence, the exact fraction is $0.555$ b). % difference = $\frac{0.555-0.5}{0.5}\times100=11$%