Answer
$0.0618m^{3}$
Work Step by Step
T=300K,
P=2atm=$2.02650\times10^{5}Pa$,
N=$\frac{160}{32}=5$
By ideal gas law:-
PV=nRT
$V=\frac{5\times 8.314\times 300}{202650}=0.0618m^{3}$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 23
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