Answer
a). (3) $T_{F}=T_{C}$
b). $-40^{\circ}C=-40^{\circ}F$
Work Step by Step
a). (3) $T_{F}=T_{C}$ because we want to find the temperature at which C and F scales have same readings.
b). Let $T_{F}=T_{C}=T$
Now, $F=1.8C+32$
So, $T=1.8T+32$
or, $T=-40$