College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 702: 68

Answer

$A^2 \times \Omega = W$

Work Step by Step

We can verify the units of $A^2 \times \Omega$: $A^2 \times \Omega = A^2 \times (kg~m^2~s^{-3}~A^{-2})$ $A^2 \times \Omega = kg~m^2~s^{-3}$ $A^2 \times \Omega = (kg~m^2~s~^{-2})~s^{-1}$ $A^2 \times \Omega = J~s^{-1}$ $A^2 \times \Omega = W$
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