Answer
The power dissipated by the resistor is $4.0~J$
Work Step by Step
We can find the power dissipated by the resistor:
$P = (I)~\times (emf)$
$P = (2.0~A)(2.00~V)$
$P = 4.0~J$
The power dissipated by the resistor is $4.0~J$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 18 - Problems - Page 702: 61
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