Answer
$P = 1.125~W$
Work Step by Step
We can find the maximum power consumed:
$P = (I)~\times (\Delta V)$
$P = (0.250~A)(1.50~V+1.50~V+1.50~V)$
$P = (0.250~A)(4.50~V)$
$P = 1.125~W$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 18 - Problems - Page 702: 66
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