College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 702: 65

Answer

$P = 600~J$

Work Step by Step

We can find the power rating: $P = (I)~\times (\Delta V)$ $P = (5.0~A)(120~V)$ $P = 600~J$
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