Answer
$XeF_{2}$ = $C_{6}H_{14}$ < $O_{3}$ < $NO_{2}$
Work Step by Step
Dipole moments are given below:
$O_{3}$: 0.53
$XeF_{2}$: 0
$NO_{2}$: 1.3
$C_{6}H_{14}$: 0
These can be found in reference material.
Physical Chemistry: Thermodynamics, Structure, and Change
by Atkins, Peter; de Paula, Julio
Published by
W. H. Freeman
ISBN 10:
1429290196
ISBN 13:
978-1-42929-019-7
Foundations - Topic A - Matter - Exercises - Page 23: A.9(b)
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