Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic A - Matter - Exercises - Page 23: A.13(a)

Answer

$p=42,510Pa$

Work Step by Step

$m = 65 kg, g = 9.81 m/s²$ $A = 150 cm² = 150 \times (0.01 m)² = 0.015 m²$ $p = \frac{F}{A}$. But, $F = W = mg$ $p=\frac{mg}{A}=\frac{65kg\times9.81m/s²}{0.015}=42,510Pa$
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