Chapter 6 - Gases - Exercises - The Simple Gas Laws - Page 232: 9

(a) 52.8 L (b) 7.27 L

Volume of O2, V1=26.7 L, P1=762 Torr = 762 mmHg, at constant temperature (a) P2=385 Torr= 385 mmHg, V2=to be calculated, As per Boyle’s law, at constant temperature, P1V1= P2V2 ⇒ V2=P1V1/P2=26.7 L x (762 mmHg)/(385 mmHg) = 52.8 L (b) P3=3.68 atm=3.68 x 760 mmHg= 2796.8 mmHg, V3=to be calculated, As per Boyle’s law, at constant temperature, P1V1= P3V3 ⇒ V3=P1V1/P3=26.7 L x (762 mmHg)/(2796.8 mmHg) = 7.27 L