Answer
10. Given: Volume of Ne(g) sample V1¬= 886 mL, P= 752 mmHg (kept constant),
T1= 26 oC=26+273= 299 K
(a) T2= 98 oC= 98+273=371 K, New volume, V2= to be calculated
As per Charles’s law, at constant pressure, V=kT, so,
V1/T1=V2/T2 ⇒ V2= V1T2/T1= 886 mL x (371 K)/(299 K) = 1099.3 mL
(b) T3= -20 oC= 273-20=253 K, New volume, V3= to be calculated
As per Charles’s law, at constant pressure, V=kT, so,
V1/T1=V3/T3 ⇒ V3= V1T3/T1= 886 mL x (253 K)/(299 K) = 749.7 mL
Work Step by Step
1. Pressure remains constant, it follows Charles's law, as V=kT
2. As initial volume is given for the sample and new volume can be calculated at new temperature as per the formula,
(a) V1/T1=V2/T2
(b) V1/T1=V3/T3
3. Substitute the values of different parameters in the formula d volume can be calculated
