General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 6 - Gases - Exercises - The Simple Gas Laws - Page 232: 13

Answer

38500 mmHg

Work Step by Step

We find: $P_{1}V_{1}=P_{2}V_{2}$ (at constant n and T) $\implies P_{1}=\frac{P_{2}V_{2}}{V_{1}}$ $=\frac{(721\,mmHg)(1875\,L+35.8\,L)}{35.8\,L}$ $=38500\, mmHg$
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