Answer
80.07 L
Work Step by Step
We find:
Moles of $Cl_{2}$= $250.0\,g\,Cl_{2}\times\frac{1\,mol\,Cl_{2}}{70.906\,g\,Cl_{2}}$
$=3.5258\,mol$
1 mol occupies 22.711 L at STP.
$\implies $ 3.5258 mol occupies $22.711\times3.5258\,L=80.07\,L$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 6 - Gases - Exercises - The Simple Gas Laws - Page 232: 18
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