Answer
(a) ruthenium (II) sulfide
(b) palladium (II) chloride
(c) silver oxide
(d) tungsten (VI) oxide
(e) platinum (IV) oxide
Work Step by Step
Transition metal elements often have several oxidation numbers. To specify which oxidation number a particular transition metal atom has in a specific compound, Roman numerals inside parentheses are placed after the name of the transition metal. Then, we add the name of the anion, changing its ending to $-ide$.
(a) Ru stands for ruthenium; S stands for sulfur. We look first at the charge on the anion. Sulfur has a charge of $2-$. If ruthenium and sulfur have a one-to-one relationship, that means that ruthenium must have a charge of $2+$ to balance out the charge on sulfur. Therefore, the name of this compound is ruthenium (II) sulfide.
(b) Pd stands for palladium; Cl stands for chlorine. We look first at the charge on the anion. Chlorine has a charge of $1-$. If palladium and chlorine have a one-to-two relationship, that means that palladium must have a charge of $2+$ ($+2 · 1 = +2$) to balance out the charge on chlorine ($-1 · 2 = -2$). Therefore, the name of this compound is palladium (II) chloride.
(c) Ag stands for silver; $O$ stands for oxygen. Silver has only one oxidation number: 1+; therefore, we do not need to specify which oxidation number with a Roman numeral. Oxygen has a charge of $2-$. Thus, silver has a two-to-one relationship with oxygen. We name this compound like other ionic compounds: keep the name of the cation as-is and follow it with the name of the anion, changing its ending to $-ide$. The name of this compound is silver oxide.
(d) W stands for tungsten; $O$ stands for oxygen. We look first at the charge on the anion. oxygen has a charge of $2-$. If tungsten and oxygen have a one-to-three relationship, that means that tungsten must have a charge of $6+$ ($+6 · 1 = +6$) to balance out the charge on oxygen ($-2 · 3 = -6$). The number of atoms for each element has been reduced to the smallest whole number ratio. Therefore, the name of this compound is tungsten (VI) oxide.
(e) Pt stands for platinum; O stands for oxygen. We look first at the charge on the anion. oxygen has a charge of $2-$. If platinum and oxygen have a one-to-two relationship, that means that platinum must have a charge of $4+$ ($+4 · 1 = +4$) to balance out the charge on oxygen ($-2 · 2 = -4$). The number of atoms for each element has been reduced to the smallest whole number ratio. Therefore, the name of this compound is platinum (IV) oxide.
