Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.48c

C6H6NO

62.1 C ; 5.21 H ; 12.1 N ; Remainder O Find O by adding masses together and subtracting from 100. O = 20.59 Convert grams to moles. C = 62.1(g/mole)/12(g)= 5.18 moles H = 5.21 (g/mole)/1.008(g) = 5.17 moles N = 12.1 (g/mole)/14.01(g) = 0.864 moles O = 20.59 (g/mole)/16(g) = 1.29 moles Divide by the smallest amount of moles. 5.18/0.864 = 5.99; 5.17/0.864 = 5.98 ; 0.864/0.864 = 1 ; 1.29/0.864 = 1.49 6 ; 6 ; 1 ; 1