Answer
5.00 mg of that substance contains $ 3.08 \times 10^{-5} \space mole \space of \space allicin$.
Work Step by Step
1. Identify the conversion factors:
- $mg$ to grams : $\frac{1 \space g}{1000 \space mg}$
- Grams (allicin) to moles (allicin): $\frac{1 \space mole \space (allicin)}{162.28 \space g \space (allicin)**}$
** This was calculated in 3.39a
2. Calculate the number of moles in 5.00 mg of that substance.
$5.00 \space mg \space (allicin) \times \frac{1 \space g}{1000 \space mg} \times \frac{1 \space mole \space (allicin)}{162.28 \space g \space (allicin) }=$
$ 3.08 \times 10^{-5} \space mole \space (allicin)$
