Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.40a

Answer

The molar mass of aspartame is equal to $294.3 \space g/mole$

Work Step by Step

Molar Mass ($C_{14}H_{18}N_2O_5$): $C: 12.01g * 14= 168.1g $ $H: 1.008g * 18= 18.14g $ $N: 14.01g * 2= 28.02g $ $O: 16.00g * 5= 80.00g $ $ 168.1g + 18.14g + 28.02g + 80.00g = 294.3g$

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