Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.45b

Answer

Fe2O3

Work Step by Step

We have 11.66g Iron and 5.01g Oxygen. First we need to get these in moles. Iron is 55.85 g/mol so 11.66 g = 0.208 mole Oxygen is 16 g/mol so 5.01g = 0.313 mole Then we divide by the smallest number, which is 0.208 0.208/0.208 = 1 0.313/0.208 = 1.5 The ratio is 1:1.5 which is the same as 2:3 Therefore we have Fe2O3

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