Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 2 - Exercises - Page 82: 121

Answer

106.91 amu

Work Step by Step

Then the mass of Ag-109 is 1.0187z. 100% - 51.839% = 48.161% Ag-109 0.51839z + 0.48161(1.0187z) = 107.87 Solve for z algebraically: z = 106.91 amu
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