Answer
a. 619 g of $P$
b. 310. g of $P$
c. 155 g of $P$
Work Step by Step
a.
- Each $ P_4O_6 $ has 4 P atoms, thus:$$ 5.00 \space mole \space P_4O_6 \times \frac{ 4 \space moles \ P }{1 \space mole \space P_4O_6 } = 20.0 \space moles \space P $$
- Calculate or find the molar mass for $ P $:
$ P $ : 30.97 g/mol
- Using the molar mass as a conversion factor, find the mass in g:
$$ 20.0 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 619 \space g$$
b. - Each $ Ca_3(PO_4)_2 $ has 2 P atoms, thus:$$ 5.00 \space mole \space Ca_3(PO_4)_2 \times \frac{ 2 \space moles \ P }{1 \space mole \space Ca_3(PO_4)_2 } = 10.0 \space moles \space P $$
- Using the molar mass as a conversion factor, find the mass in g:
$$ 10.0 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 310. \space g$$
c,- Each $ Na_2HPO_4 $ has 1 P atoms, thus:$$ 5.00 \space mole \space Na_2HPO_4 \times \frac{ 1 \space moles \ P }{1 \space mole \space Na_2HPO_4 } = 5.00 \space moles \space P $$
$$ 5.00 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 155 \space g$$
