Answer
a.
$$ 85.2 \space g$$
b.
$$ 160. \space g$$
c, $$ 1260 \space g$$
Work Step by Step
a. - Using the molar mass as a conversion factor, find the mass in g:
$$ 5.00 \space mole \times \frac{ 17.03 \space g}{1 \space mole} = 85.2 \space g$$
b.
$$ 5.00 \space mole \times \frac{ 32.05 \space g}{1 \space mole} = 160. \space g$$
c, $$ 5.00 \space mole \times \frac{ 252.08 \space g}{1 \space mole} = 1.26 \times 10^3 \space g$$
