Answer
$HClO_4$, $HClO_2$, $N{H_4}^+$ and $H_2O$
Work Step by Step
Using table 13-2, from page 531, and knowing that:
Strong acids: $K_a > 1$
Water: $K_a = 1.0 \times 10^{-14}$
Identify each acid ka value:
$HClO_2$: $K_a = 1.2 \times 10^{-2}$
$H_2O$: $K_a = 1.0 \times 10^{-14}$
$N{H_4}^+$: $K_a = 5.6 \times 10^{-10}$
$HClO_4$: $K_a > 1$
- Ordering in decreasing order, we obtain:
$HClO_4, HClO_2, N{H_4}^+, H_2O$
- Remember that a greater $K_a$ value means a stronger acid.