Answer
a.
Acid: $Al(H_2O)_6^{3+}$
Base: $H_2O$
Conj. Base: $Al(H_2O)_5(OH)^{2+}$
Conj. Acid: $H_3O^+$
b.
Acid: $HON{H_3}^+$
Base: $H_2O$
Conj. base: $HONH_2$
Conj. acid: $H_3O^+$
c.
Acid: $HOCl$
Base: $C_6H_5NH_2$
Conj. base: $OCl^-$
Conj. acid: $C_6H_5N{H_3}^+$
Work Step by Step
- Analyze the reactions, and identify the compound that is donating one proton in the direct reaction (left to right); this is the acid, and the product of losing this proton is the conjugate base.
- Identify the compound that is receiving one proton in the direct reaction (left to right); this is the base, and the product of gaining this proton is the conjugate acid.
