Answer
Perchloric acid: $HClO_4(aq) + H_2O(l) -- \gt Cl{O_4}^-(aq) + H_3O^+(aq)$
Propanoic acid: $CH_3CH_2CO_2H(aq) + H_2O(l) \lt -- \gt CH_3CH_2C{O_2}^-(aq) + H_3O^+(aq)$
Work Step by Step
In a dissociation of an acid in water, the acid donates a $H^+$ to the $H_2O$ molecule, producing its conjugate base and hydronium ion $(H_3O^+)$.
