Answer
$76.9\ mL$
Work Step by Step
Number of moles of NaOH:
$35.2\ mL\times 0.546\ M=19.2\ mmol$
From stoichiometry:
$9.6\ mmol\ H_2C_2O_4$
Volume required:
$9.6\ mmol\div 0.125\ M= 76.9\ mL$
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