Answer
See answer below.
Work Step by Step
a) $[H_3O^+]=10^{-1.00}=0.1\ M$,
Acidic
b) $[H_3O^+]=10^{-10.50}=3.16\times10^{-11}\ M$,
Basic
c) $pH=-log(1.3\times10^{-5}\ M)=4.88$
Acidic
d) $pH=-log(2.3\times10^{-8}\ M)=7.64$
Basic
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 59
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