Answer
$268\ mL$
Work Step by Step
Number of moles of the base:
$2.50\ g\div171.34\ g/mol=0.0146\ mol$
From stoichiometry, number of moles of acid required:
$0.0292\ mol$
Volume required:
$0.0292\ mol\div0.109\ M=0.268\ L=268\ mL$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 61
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