Answer
See answer below.
Work Step by Step
a) $pH=-log(6.7\times10^{-10}\ M)=9.17$
Basic
b) $pH=-log(2.2\times10^{-6}\ M)=5.68$
Acidic
c) $[H_3O^+]=10^{-5.25}=5.62\times10^{-6}\ M$,
Acidic
d) $pH=-log(2.5\times10^{-2}\ M)=1.60$
Acidic
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