Answer
See answer below.
Work Step by Step
From stoichiometry:
$6.2\ mol\ Fe_2O_3\times 3\ mol\ C/2\ mol\ Fe_2O_3= 9.3\ mol\ C\ required$
$6.2\ mol\ Fe_2O_3\times 3\ mol\ CO_2/2\ mol\ Fe_2O_3 =9.3\ mol\ CO_2\ produced$
$6.2\ mol\ Fe_2O_3\times 4\ mol\ Fe/2\ mol\ Fe_2O_3=12.4\ mol\ Fe\ produced$