Answer
a)$317.5\ g\ Fe$
b) $238.6\ g\ CO$
Work Step by Step
a) Number of moles of oxide:
$454\ g\div159.688\ g/mol=2.84\ mol$
From stoichiometry:
$2.84\ mol\times2/1\times55.845\ g/mol\ Fe=317.5\ g\ Fe$
b) From stoichiometry:
$2.84\ mol\times3/1\times 28.01\ g/mol\ CO=238.6\ g\ CO$
