Answer
$3.75\ mol\ O_2$
$2.5\ mol\ PbO$
$2.5\ mol\ SO_2$
Work Step by Step
From stoichiometry:
$2.5\ mol\times3_{O_2}/2_{PbS}=3.75\ mol\ O_2$
$2.5\ mol\times2_{PbO}/2_{PbS}=2.5\ mol\ PbO$
$2.5\ mol\times2_{SO_2}/2_{PbS}=2.5\ mol\ SO_2$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179a: 7
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