Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553b: 27

Answer

$t=17\ h$

Work Step by Step

For a first-order reaction; $ln(C/C_0)=-k.t; k=0.693/t_{1/2}$ $ln(2.00\times10^{-4}\ mol/L\div 3.6\times10^{-3}\ mol/L)=-0.693/245\ min\times t$ $t=1021.85\ min=17\ h$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.