Answer
See the answer below.
Work Step by Step
For a first-order reaction:
$ln(C/C_0)=-kt$
Assuming constant volume, we can use this equation on a mass basis.
$ln(m/2.00\ g)=-0.0216\ min^{-1}\times 3\ min\rightarrow m=1.87\ g$
Consumed moles: $(2.00-1.87)\ g\div58.08\ g/mol=0.0022\ mol$
Formed N2 mass: $0.0022\ mol\times 28.01\ g/mol=0.060\ g$
